132=x^2-x

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Solution for 132=x^2-x equation:



132=x^2-x
We move all terms to the left:
132-(x^2-x)=0
We get rid of parentheses
-x^2+x+132=0
We add all the numbers together, and all the variables
-1x^2+x+132=0
a = -1; b = 1; c = +132;
Δ = b2-4ac
Δ = 12-4·(-1)·132
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-23}{2*-1}=\frac{-24}{-2} =+12 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+23}{2*-1}=\frac{22}{-2} =-11 $

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